Chemistry · IUPAC Nomenclature

NEET (UG) 2024 — Question 63

A compound with a molecular formula of CX6HX14\ce{C6H14} has two tertiary carbons. Its IUPAC name is:

  1. Option A:

    n-hexane

  2. Option B:

    2-methylpentane

  3. Option C:

    2,3-dimethylbutane

    Correct
  4. Option D:

    2,2-dimethylbutane

Answer: C

Step-by-step solution

A tertiary carbon is one that is bonded to three other carbon atoms. For CX6HX14\ce{C6H14}, draw each isomeric structure and count the carbon types. n-Hexane: CHX3−CHX2−CHX2−CHX2−CHX2−CHX3\ce{CH3-CH2-CH2-CH2-CH2-CH3} has no tertiary carbon. 2-Methylpentane: CHX3−CH(CHX3)−CHX2−CHX2−CHX3\ce{CH3-CH(CH3)-CH2-CH2-CH3} has only one tertiary carbon (C-2). 2,3-Dimethylbutane: CHX3−CH(CHX3)−CH(CHX3)−CHX3\ce{CH3-CH(CH3)-CH(CH3)-CH3} has two tertiary carbons (C-2 and C-3). 2,2-Dimethylbutane: CHX3−C(CHX3)X2−CHX2−CHX3\ce{CH3-C(CH3)2-CH2-CH3} has a quaternary carbon and no tertiary carbon. Therefore, the compound with two tertiary carbons is 2,3-dimethylbutane, option C.

Answer key and solution verified before publishing.

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Exam
NEET (UG) 2024
Subject
Chemistry
Chapter
IUPAC Nomenclature
Topic
Basics of IUPAC naming + Naming Hydrocarbons
A compound with a molecular formula of ce C6H14 has two tertiary… | NEET (UG) 2024 PYQ with Solution · DhiX AI