Chemistry · Coordination Compounds

JEE Main 2024 — 5 April, Shift 1 — Question 67

Which one of the following complexes will exhibit the least paramagnetic behaviour?

[Atomic number, Cr=24,Mn=25,Fe=26,Co=27\mathrm{Cr}=24, \mathrm{Mn}=25, \mathrm{Fe}=26, \mathrm{Co}=27 ]

  1. Option A:

    [Co(H2O)6]2+\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}

    Correct
  2. Option B:

    [Fe(H2O)6]2+\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}

  3. Option C:

    [Mn(H2O)6]2+\left[\mathrm{Mn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}

  4. Option D:

    [Cr(H2O)6]2+\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}

Answer: A

Step-by-step solution

Number of unpaired eμ=n(n+2)\mu =\sqrt{\text{n}\left( \text{n}+2 \right)} B.M.
[Co(H2O)6]2+{{\left[ \text{Co}{{\left( {{\text{H}}_{2}}\text{O} \right)}_{6}} \right]}^{2+}}33.87
[Fe(H2O)6]2+{{\left[ \text{Fe}{{\left( {{\text{H}}_{2}}\text{O} \right)}_{6}} \right]}^{2+}}44.89
[Mn(H2O)6]2+{{\left[ \text{Mn}{{\left( {{\text{H}}_{2}}\text{O} \right)}_{6}} \right]}^{2+}}55.92
[Cr(H2O)6]2+{{\left[ \text{Cr}{{\left( {{\text{H}}_{2}}\text{O} \right)}_{6}} \right]}^{2+}}44.89

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Chemistry
Chapter
Coordination Compounds
Topic
Properties and importance of Coordination Complexes