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Chemistry · d and f Block Elements

JEE Main 2024 — 1 February, Shift 2 — Question 66

Which of the following compounds show colour due to d-d transition?

  1. Option A:

    CuSO4⋅5H2O\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}

    Correct
  2. Option B:

    K2Cr2O7\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}

  3. Option C:

    K2CrO4\mathrm{K}_{2} \mathrm{CrO}_{4}

  4. Option D:

    KMnO4\mathrm{KMnO}_{4}

Answer: A

Step-by-step solution

CuSO4.5H2O\mathrm{CuSO}_{4} .5 \mathrm{H}_{2} \mathrm{O}

Cu2+:3 d94 s0\mathrm{Cu}^{2+}: 3 \mathrm{~d}^{9} 4 \mathrm{~s}^{0}

unpaired electron present so it show colour due to d-d transition.

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
1 February, Shift 2
Subject
Chemistry
Chapter
d and f Block Elements
Topic
Properties of compounds of 3d Series elements + Comparison between 3d, 4d, 5d

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