Physics · Semiconductor and Electronic Devices

JEE Main 2026 — 22 January, Evening Shift — Question 34

When a part of a straight capillary tube is placed vertically in a liquid, the liquid raises upto certain height h . If the inner radius of the capillary tube, density of the liquid and surface tension of the liquid decrease by $1 \%$ each, then the height of the liquid in the tube will change by $\_\_\_\_$ %.

Option A:
$-1$
Option B:
$+3$
Option C:
$-3$
Option D:
$+1$
Correct

Answer: D

Step-by-step solution

$\mathrm{h}=\frac{2 \mathrm{~T} \cos \theta}{\rho \mathrm{gr}}$

\begin{aligned} & \frac{\Delta h}{h} \%=\frac{\Delta T}{T} \%-\frac{\Delta \rho}{\rho} \%-\frac{\Delta r}{r} \% & \frac{\Delta h}{h} \%=1+1+1 & \frac{\Delta h}{h}=+1 \% \end{aligned}

Answer key and solution verified before publishing.

Practise Semiconductor and Electronic Devices

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free

Exam: JEE Main 2026
Paper: 22 January, Evening Shift
Subject: Physics
Chapter: Semiconductor and Electronic Devices
Topic: Boolean Algebra, Truth Tables and Logic Gates