JEE Main 2026 — 22 January, Evening Shift — Question 35

$\mathrm{P}_{\text {out }}=1000 \mathrm{~W}$ $\mathrm{P}=\mathrm{VI}$ $1000=250 \times \mathrm{I}$ $\mathrm{I}=4 \mathrm{~A}$ $\mathrm{P}_{\text {loss }}=\mathrm{I}^{2} \mathrm{R}=(4)^{2} \times 2=3200$ $\mathrm{P}_{\text {net }}=1000+32=103200$ $\eta=\left(\frac{P_{\text {out }}}{P_{\text {net }}}\right) \times 100=\frac{1000}{1032} \times 100=96.9 \%$