Chemistry · Practical Organic Chemistry

JEE Main 2026 — 22 January, Evening Shift — Question 50

When 1 g of compound ( X ) is subjected to Kjeldahl's method for estimation of nitrogen, 15 mL,1MH2SO4\mathrm{mL}, 1 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4} was neutralized by ammonia evolved. The percentage of nitrogen in compound (X)(\mathrm{X}) is :

  1. Option A:

    21

  2. Option B:

    0.42

  3. Option C:

    42

    Correct
  4. Option D:

    0.21

Answer: C

Step-by-step solution

eq. of H2SO4=\mathrm{H}_{2} \mathrm{SO}_{4}= eq. of Ammonia ⇒15×1×21000=\Rightarrow \frac{15 \times 1 \times 2}{1000}= moles of ammonia ×1\times 1 ⇒ Moles of ammonia == moles of ' N ' ⇒ Weight of nitrogen =15×1×21000×14=0.42=\frac{15 \times 1 \times 2}{1000} \times 14=0.42 %\% weight of ' N′=0.421×100=42%\mathrm{N}^{\prime}=\frac{0.42}{1} \times 100=42 \%

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Chemistry
Chapter
Practical Organic Chemistry
Topic
Quantitative organic analysis
When 1 g of compound ( X ) is subjected to Kjeldahl's method for… | JEE Main 2026 PYQ with Solution · DhiX AI