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Physics · Thermal Properties of Matter

JEE Main 2025 — 8 April, Evening Shift — Question 63

Water falls from a height of 200 m into a pool. Calculate the rise in temperature of the water assuming no heat dissipation from the water in the pool. (Take g=10 m/s2g=10 \mathrm{~m} / \mathrm{s}^{2}, specific heat of water =4200 J/(kg=4200 \mathrm{~J} /(\mathrm{kg} K))

  1. Option A:

    0.36 K

  2. Option B:

    0.23 K

  3. Option C:

    0.48 K

    Correct
  4. Option D:

    0.14 K

Answer: C

Step-by-step solution

mgh=msΔTm g h=m s \Delta T

ΔT=ghS=10×2004200=0.48 K\Delta T=\frac{g h}{S}=\frac{10 \times 200}{4200}=0.48 \mathrm{~K}

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
8 April, Evening Shift
Subject
Physics
Chapter
Thermal Properties of Matter
Topic
Thermometry and Calorimetry
Water falls from a height of 200 m into a pool. Calculate the rise in… | JEE Main 2025 PYQ with Solution · DhiX AI