Two persons pull a wire towards themselves. Each person exerts a force of 200 N on the wire. Young's modulus of the material of wire is 1 × 10 11 N m -2 . Original length of the wire is 2 m and the area of cross section is 2 cm 2 . The wire will extend in length by μ m .

Physics · Mechanical Properties of Matter

JEE Main 2024 — 9 April, Shift 1 — Question 56

Two persons pull a wire towards themselves. Each person exerts a force of 200 N on the wire. Young's modulus of the material of wire is $1 \times 10^{11} \mathrm{~N} \mathrm{~m}^{-2}$ . Original length of the wire is 2 m and the area of cross section is $2 \mathrm{~cm}^{2}$ . The wire will extend in length by $\qquad$ $\mu \mathrm{m}$ .

Answer: 20

Numerical answer — enter this value.

Step-by-step solution

$\begin{array}{*{35}{r}}{} & \frac{\text{F}}{\text{ }\!\!~\!\!\text{ A}}=\text{Y}\frac{\text{ }\!\!\Delta\!\!\text{ }\ell }{\ell }\Rightarrow \text{ }\!\!\Delta\!\!\text{ }\ell =\frac{\text{F}\ell }{\text{AY}}\\{} & \text{ }\!\!\Delta\!\!\text{ }\ell =\frac{200\times 2}{2\times {{10}^{-4}}\times {{10}^{11}}}=2\times {{10}^{-5}}=20\mu \text{ }\!\!~\!\!\text{ m}\\\end{array}$

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Exam: JEE Main 2024
Paper: 9 April, Shift 1
Subject: Physics
Chapter: Mechanical Properties of Matter
Topic: Stress,Strain and Modulus of Elasticity