Physics · Geometrical Optics

JEE Main 2025 — 29 January, Evening Shift — Question 23

Two identical symmetric double convex lenses of focal length ff are cut into two equal parts L1, L2\mathrm{L}_{1}, \mathrm{~L}_{2} by AB plane and L3,L4L_{3}, L_{4} by XY plane as shown in figure respectively. The ratio of focal lengths of lenses L1L_{1} and L3L_{3} is

Question figure
  1. Option A:

    1:41: 4

  2. Option B:

    1:11: 1

  3. Option C:

    2:12: 1

  4. Option D:

    1:21: 2

    Correct

Answer: D

Step-by-step solution

fL1=fL2=ff_{L_{1}}=f_{L_{2}}=f

fL3=fL4=2f\mathrm{f}_{\mathrm{L}_{3}}=\mathrm{f}_{\mathrm{L}_{4}}=2 \mathrm{f}

∴fL1:fL3=1:2\therefore \mathrm{f}_{\mathrm{L}_{1}}: \mathrm{f}_{\mathrm{L}_{3}}=1: 2

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Physics
Chapter
Geometrical Optics
Topic
Experiments for Determination of Focal Length of Lens & Mirrors
Two identical symmetric double convex lenses of focal length f are… | JEE Main 2025 PYQ with Solution · DhiX AI