Mathematics · Probability

JEE Main 2026 — 22 January, Morning Shift — Question 4

Two distinct numbers a and b are selected at random from 1,2,3,……,501,2,3, \ldots \ldots, 50. The probability, that their product ab is divisible by 3 , is

  1. Option A:

    5611225\frac{561}{1225}

  2. Option B:

    6641225\frac{664}{1225}

    Correct
  3. Option C:

    2721225\frac{272}{1225}

  4. Option D:

    825\frac{8}{25}

Answer: B

Step-by-step solution

Two distinct numbers a,b a,b are chosen from {1,2,…,50}. \{1,2,\dots,50\}.

Total number of ways:

(502)=1225\binom{50}{2}=1225

The product abab is divisible by 33 if at least one of a,ba,b is divisible by 33.

Count multiples of 3

⌊503⌋=16\left\lfloor \frac{50}{3} \right\rfloor = 16

So, Multiples of 3=16,3 =16,\qquad

Non-multiples of 3=50−16=343=50-16=34

Count unfavorable cases

Unfavorable case: neither aa nor bb is divisible by 3.

(342)=34⋅332=561\binom{34}{2}=\frac{34\cdot33}{2}=561

Favorable cases

Favorable = 1225-561=664

Probability

P=6641225P=\frac{664}{1225} 6641225\boxed{\frac{664}{1225}}

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Mathematics
Chapter
Probability
Topic
Introduction to Probability
Two distinct numbers a and b are selected at random from 1,2,3, ldots… | JEE Main 2026 PYQ with Solution · DhiX AI