Chemistry · d and f Block Elements
JEE Main 2024 — 27 January, Shift 2 — Question 75
Total number of ions from the following with noble gas configuration is .
and
Answer: 3
Numerical answer — enter this value.
Step-by-step solution
Noble gas configuration
\begin{array}{*{35}{r}}{} & \left[ \text{S}{{\text{r}}^{2+}} \right]=\left[ \text{Kr} \right]\\{} & \left[ \text{C}{{\text{s}}^{+}} \right]=\left[ \text{Xe} \right] \\{} & \left[ \text{Y}{{\text{b}}^{2+}} \right]=\left[ \text{Kr} \right]4\text{ }\!\!~\!\!\text{ }{{\text{d}}^{10}}4{{\text{f}}^{14}}5\text{ }\!\!~\!\!\text{ }{{\text{s}}^{2}}5{{\text{p}}^{6}}\\{} & \left[ \text{L}{{\text{a}}^{2+}} \right]=\left[ \text{Xe} \right]5\text{ }\!\!~\!\!\text{ }{{\text{d}}^{1}} \\{} & \left[ \text{ }\!\!~\!\!\text{ P}{{\text{b}}^{2+}} \right]=\left[ \text{Xe} \right]4{{\text{f}}^{14}}5\text{ }\!\!~\!\!\text{ }{{\text{d}}^{10}}6\text{ }\!\!~\!\!\text{ }{{\text{s}}^{2}} \\{} & \left[ \text{F}{{\text{e}}^{2+}} \right]=\left[ \text{Ar} \right]3\text{ }\!\!~\!\!\text{ }{{\text{d}}^{6}} \\\end{array}
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- Exam
- JEE Main 2024
- Paper
- 27 January, Shift 2
- Subject
- Chemistry
- Chapter
- d and f Block Elements
- Topic
- Introduction and Properties of Transition Elements