Chemistry · d and f Block Elements

JEE Main 2024 — 27 January, Shift 2 — Question 61

Given below are two statements, one is labelled as Statement I and the other is labelled as Statement II.

Statement (I) : In the Lanthanoids, the formation of $\mathrm{Ce}^{4+}$ is favoured by its noble gas configuration.

Statement (II) : $\mathrm{Ce}^{4+}$ is a strong oxidant reverting to the common +3 state.

In the light of the above statements, choose the most appropriate answer from the options given below:

Option A:
Statement I is false but Statement II is true
Option B:
Both Statement I and Statement II are true
Correct
Option C:
Statement I is true but Statement II is false
Option D:
Both Statement I and Statement II are false

Answer: B

Step-by-step solution

Statement (I) is true: Cerium has the electronic configuration $[\mathrm{Xe}]\,4f^1 5d^1 6s^2$ . On forming $\mathrm{Ce^{4+}}$ , it attains the noble gas configuration $[\mathrm{Xe}]$ $(4f^0)$ , which stabilises the +4 oxidation state and favours its formation.

Statement (II) is true: $\mathrm{Ce^{4+}}$ readily gets reduced to the more stable and common +3 oxidation state. Hence, $\mathrm{Ce^{4+}}$ acts as a strong oxidising agent.

Thus, both Statement I and Statement II are true $\rightarrow$ Option B.

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Exam: JEE Main 2024
Paper: 27 January, Shift 2
Subject: Chemistry
Chapter: d and f Block Elements
Topic: Inner transition elements (f-Block elements)

Answer: B

Step-by-step solution

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