Physics · Sound Waves

JEE Main 2026 — 23 January, Evening Shift — Question 46

The velocity of sound in air is doubled when the temperature is raised from $0^{\circ} \mathrm{C}$ to $\alpha^{\circ} \mathrm{C}$ . The value of $\alpha$ is $\_\_\_\_$ .

Answer: 819

Numerical answer — enter this value.

Step-by-step solution

$\mathrm{V}=\sqrt{\frac{\gamma \mathrm{RT}}{\mathrm{M}}}$ $\frac{\mathrm{V}_{1}}{\mathrm{~V}_{2}}=\frac{\sqrt{\mathrm{T}_{1}}}{\sqrt{\mathrm{~T}_{2}}}$ $\frac{\mathrm{V}_{0}}{2 \mathrm{~V}_{0}}=\sqrt{\frac{273}{\mathrm{~T}_{2}}}$ $\frac{1}{4}=\frac{273}{\mathrm{~T}_{2}}$ $\mathrm{T}_{2}=4 \times 273=\alpha+273$ $\alpha=3 \times 273$ $\alpha=819^{\circ} \mathrm{C}$

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Exam: JEE Main 2026
Paper: 23 January, Evening Shift
Subject: Physics
Chapter: Sound Waves
Topic: Speed, Intensity and Characteristics of Sound Waves