Chemistry · Thermodynamics & Thermochemistry

JEE Main 2026 — 23 January, Evening Shift — Question 47

It is noticed that Pb2+\mathrm{Pb}^{2+} is more stable than Pb2+\mathrm{Pb}^{2+} but Sn2+\mathrm{Sn}^{2+} is less stable than Sn4+\mathrm{Sn}^{4+}. Observe the following reactions

\mathrm{PbO}_{2}+\mathrm{Pb} \rightarrow 2 \mathrm{PbO} ; \Delta_{\mathrm{r}} \mathrm{G}^{\circ} \end{gathered}$$ $$\begin{gathered} \mathrm{SnO}_{2}+\mathrm{Sn} \rightarrow 2 \mathrm{SnO} ; \Delta_{\mathrm{r}} \mathrm{G}^{\circ} \end{gathered}$$ Identify the correct set from the following.
  1. Option A:

    ΔrG∘(1)>0;ΔrG∘(2)<0\Delta_{\mathrm{r}} \mathrm{G}^{\circ}(1)>0 ; \Delta_{\mathrm{r}} \mathrm{G}^{\circ}(2)<0

  2. Option B:

    ΔrG∘(1)<0;ΔrG∘(2)<0\Delta_{\mathrm{r}} \mathrm{G}^{\circ}(1)<0 ; \Delta_{\mathrm{r}} \mathrm{G}^{\circ}(2)<0

  3. Option C:

    ΔrG∘(1)<0;ΔrG∘(2)>0\Delta_{\mathrm{r}} \mathrm{G}^{\circ}(1)<0 ; \Delta_{\mathrm{r}} \mathrm{G}^{\circ}(2)>0

    Correct
  4. Option D:

    ΔrG∘(1)>0;ΔrG∘(2)>0\Delta_{\mathrm{r}} \mathrm{G}^{\circ}(1)>0 ; \Delta_{\mathrm{r}} \mathrm{G}^{\circ}(2)>0

Answer: C

Step-by-step solution

PbO2+Pb→2PbO\mathrm{PbO}_{2}+\mathrm{Pb} \rightarrow 2 \mathrm{PbO} Pb2+\mathrm{Pb}^{2+} is more stable hence reaction will be spontaneous. So ΔG∘r(1)\Delta \mathrm{G}^{\circ}{ }_{\mathrm{r}}(1) is negative. SnO2+Sn→2SnO\mathrm{SnO}_{2}+\mathrm{Sn} \rightarrow 2 \mathrm{SnO} Sn+2\mathrm{Sn}^{+2} is less stable, so reaction will be nonspontaneous hance ΔG∘r(2)\Delta \mathrm{G}^{\circ}{ }_{\mathrm{r}}(2) is positive.

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Chemistry
Chapter
Thermodynamics & Thermochemistry
Topic
Gibbs Free Energy - Relation with Equilibrium, Metallurgy and Electrochemistry
It is noticed that Pb 2+ is more stable than Pb 2+ but Sn 2+ is less… | JEE Main 2026 PYQ with Solution · DhiX AI