Mathematics · Definite Integration

JEE Main 2026 — 22 January, Morning Shift — Question 14

The value of ∫−π2π2(1[x]+4)dx\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}}\left(\frac{1}{[x]+4}\right) d x, where [∙][\bullet] denotes the greatest integer function, is

  1. Option A:

    160(21π−1)\frac{1}{60}(21 \pi-1)

  2. Option B:

    160(π−7)\frac{1}{60}(\pi-7)

  3. Option C:

    760(3π−1)\frac{7}{60}(3 \pi-1)

    Correct
  4. Option D:

    760(π−3)\frac{7}{60}(\pi-3)

Answer: C

Step-by-step solution

I=∫−π/2π/21[x]+4dxI=\int_{-\pi / 2}^{\pi / 2} \frac{1}{[x]+4} d x

I=∫−π/2−1dx2+∫−10dx3+∫10dx4+∫1π/2dx5\mathrm{I}=\int_{-\pi / 2}^{-1} \frac{\mathrm{dx}}{2}+\int_{-1}^{0} \frac{\mathrm{dx}}{3}+\int_{1}^{0} \frac{\mathrm{dx}}{4}+\int_{1}^{\pi / 2} \frac{\mathrm{dx}}{5}

=12(−1+π2)+13(1)+14(1)+(π2−1)15=\frac{1}{2}\left(-1+\frac{\pi}{2}\right)+\frac{1}{3}(1)+\frac{1}{4}(1)+\left(\frac{\pi}{2}-1\right) \frac{1}{5}

=7π20−760=760(3π−1)=\frac{7 \pi}{20}-\frac{7}{60}=\frac{7}{60}(3 \pi-1)

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Mathematics
Chapter
Definite Integration
Topic
Evaluation of Definite Integrals
The value of int -π/2 π/2 (1/[x]+4 ) d x , where [bullet] denotes the… | JEE Main 2026 PYQ with Solution · DhiX AI