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Physics · Units, Dimensions & Error Analysis

JEE Main 2025 — 7 April, Evening Shift — Question 47

The unit of 2Iϵ0c\sqrt{\frac{2 I}{\epsilon_{0} c}} is : ( I=I= intensity of an electromagnetic wave, cc : speed of light)

  1. Option A:

    NC

  2. Option B:

    Vm

  3. Option C:

    NC−1\mathrm{NC}^{-1}

    Correct
  4. Option D:

    Nm

Answer: C

Step-by-step solution

For 2lϵ⋅c\sqrt{\frac{2 l}{\epsilon \cdot c}} Unit of I⇒J S⋅ m2I \Rightarrow \frac{J}{\mathrm{~S} \cdot \mathrm{~m}^{2}} Unit of C⇒ m/sC \Rightarrow \mathrm{~m} / \mathrm{s}

Unit of ⇒C2m−2N−1\Rightarrow C^{2} m^{-2} N^{-1},

C⇒C \Rightarrow Amp. Sec. N=kg⋅m/s2N=\mathrm{kg} \cdot \mathrm{m} / \mathrm{s}^{2}

Putting =NC=\frac{N}{C}

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
7 April, Evening Shift
Subject
Physics
Chapter
Units, Dimensions & Error Analysis
Topic
Units and Dimensions Analysis

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