Physics · Units, Dimensions & Error Analysis

JEE Main 2025 — 7 April, Evening Shift — Question 49

Match List-I with List-II. Choose the correct answer from the options given below:

List-IList-II
a. Mass density(I) [ML2  ⁣ ⁣  ⁣ ⁣ T−3]\left[ \text{M}{{\text{L}}^{2}}\text{ }\!\!~\!\!\text{ }{{\text{T}}^{-3}} \right]
b. Impulse(ii) [MLT−1]\left[ \text{ML}{{\text{T}}^{-1}} \right]
c. Power(III) [ML2  ⁣ ⁣  ⁣ ⁣ T0]\left[ \text{M}{{\text{L}}^{2}}\text{ }\!\!~\!\!\text{ }{{\text{T}}^{0}} \right]
d. Moment of inertia(iv) [ML−3  ⁣ ⁣  ⁣ ⁣ T0]\left[ \text{M}{{\text{L}}^{-3}}\text{ }\!\!~\!\!\text{ }{{\text{T}}^{0}} \right]
  1. Option A:

    a(iv),b(ii),c(i),d(iii)a(i v), b(i i), c(i), d(i i i)

    Correct
  2. Option B:

    a(i),b(a(i), b( iii ),c(iv),d(ii)), c(i v), d(i i)

  3. Option C:

    a(ii),b(iii),c(iv),d(i)a(i i), b(i i i), c(i v), d(i)

  4. Option D:

    a(iv),b(ii),c(iii),d(i)a(i v), b(i i), c(i i i), d(i)

Answer: A

Step-by-step solution

ρ=kgm3⇒[ML−3 T0]\rho=\frac{\mathrm{kg}}{\mathrm{m}^{3}} \Rightarrow\left[\mathrm{ML}^{-3} \mathrm{~T}^{0}\right]

I=F⋅Δt⇒[MLT−1]I=F \cdot \Delta t \Rightarrow\left[\mathrm{M} \mathrm{LT}^{-1}\right] P=wt⇒[ML2 T−3]\begin{gathered} P=\frac{w}{t} \Rightarrow\left[\mathrm{M} \mathrm{L}^{2} \mathrm{~T}^{-3}\right] \end{gathered} I=MR2n⇒[ML2 T0]\begin{gathered} I=\frac{M R^{2}}{n} \Rightarrow\left[\mathrm{ML}^{2} \mathrm{~T}^{0}\right] \end{gathered}

(i) [ML2 T−3]\left[\mathrm{ML}^{2} \mathrm{~T}^{-3}\right]

(ii) [MLT−1]\left[\mathrm{MLT}^{-1}\right] \section*{List-II}

(iii) [ML2 T0]\left[\mathrm{ML}^{2} \mathrm{~T}^{0}\right]

(iv) [ML−3 T0]\left[\mathrm{ML}^{-3} \mathrm{~T}^{0}\right]

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Physics
Chapter
Units, Dimensions & Error Analysis
Topic
Units and Dimensions Analysis
Match List-I with List-II. Choose the correct answer from the options… | JEE Main 2025 PYQ with Solution · DhiX AI