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Physics · Semiconductor and Electronic Devices

JEE Main 2025 — 3 April, Evening Shift — Question 52

The truth table corresponding to the circuit given below is :

Question figure
  1. Option A:
    Option A figure
  2. Option B:
    Option B figure
    Correct
  3. Option C:
    Option C figure
  4. Option D:
    Option D figure

Answer: B

Step-by-step solution

Logic : C=(A+B)C=(A+B)

A=A⋅A+A⋅B=A+A⋅B=A(1+B)C=A\begin{aligned} A & =A \cdot A+A \cdot B \\ & =A+A \cdot B \\ & =A(1+B) C \\ & =A \end{aligned}

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
3 April, Evening Shift
Subject
Physics
Chapter
Semiconductor and Electronic Devices
Topic
Boolean Algebra, Truth Tables and Logic Gates
The truth table corresponding to the circuit given below is : | JEE Main 2025 PYQ with Solution · DhiX AI