Mathematics · Binomial Theorem

JEE Main 2025 — 3 April, Morning Shift — Question 23

The sum of all rational terms in the expansion of (2+3)8(2+\sqrt{3})^{8} is

  1. Option A:

    16923

  2. Option B:

    3763

  3. Option C:

    33845

  4. Option D:

    18817

    Correct

Answer: D

Step-by-step solution

S=(2+3)8S=(2+\sqrt{3})^{8}

For sum of rational terms

=8C0(2)8+8C2(2)6⋅(3)2+8C4(2)4(3)4={ }^{8} \mathrm{C}_{0}(2)^{8}+{ }^{8} \mathrm{C}_{2}(2)^{6} \cdot(\sqrt{3})^{2}+{ }^{8} \mathrm{C}_{4}(2)^{4}(\sqrt{3})^{4}

+8C6(2)2(3)6+8C8(3)8+{ }^{8} \mathrm{C}_{6}(2)^{2}(\sqrt{3})^{6}+{ }^{8} \mathrm{C}_{8}(\sqrt{3})^{8}

=28+28×26.3+70.24.9+28.22.27+81=2^{8}+28 \times 2^{6} .3+70.2^{4} .9+28.2^{2} .27+81

=256+5376+10080+3024+81=256+5376+10080+3024+81

=18817=18817

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Mathematics
Chapter
Binomial Theorem
Topic
Applications of Binomial Theorem