The 'spin only' magnetic moment value of MO 4 2- is BM. (Where M is a metal having least metallic radii. among Sc , Ti , V , Cr , Mn and Zn ). (Given atomic number : Sc =21, Ti =22, V =23 , Cr =24, Mn =25 and Zn =30 )

Chemistry · d and f Block Elements

JEE Main 2024 — 8 April, Shift 1 — Question 76

The 'spin only' magnetic moment value of $\mathrm{MO}_{4}{ }^{2-}$ is $\qquad$ BM. (Where M is a metal having least metallic radii. among

$\mathrm{Sc}, \mathrm{Ti}, \mathrm{V}, \mathrm{Cr}, \mathrm{Mn}$ and Zn ). (Given atomic number : $\mathrm{Sc}=21, \mathrm{Ti}=22, \mathrm{~V}=23$ , $\mathrm{Cr}=24, \mathrm{Mn}=25$ and

$\mathrm{Zn}=30$ )

Answer: 0

Numerical answer — enter this value.

Step-by-step solution

Metal having least metallic radii among $\mathrm{Sc}, \mathrm{Ti}, \mathrm{V}$ , $\mathrm{Cr}, \mathrm{Mn} \& \mathrm{Zn}$ is Cr .

Spin only magnetic moment of $\mathrm{CrO}_{4}{ }^{2-}$ . Here $\mathrm{Cr}^{+6}$ is in $\mathrm{d}^{0}$ configuration (diamagnetic).

Answer key and solution verified before publishing.

Practise d and f Block Elements

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free

Exam: JEE Main 2024
Paper: 8 April, Shift 1
Subject: Chemistry
Chapter: d and f Block Elements
Topic: Properties of general compounds of transition elements

Iron (III) catalyses the reaction between iodide and persulphate ions, in which A. Fe^3+ oxidises the iodide ion B. Fe^3+ oxidises the…

Answer: 0

Step-by-step solution

Practise d and f Block Elements

More d and f Block Elements questions from this paper