The refractive index of the material of a glass prism is √(3) . The angle of minimum deviation is equal to the angle of the prism. What is the angle of the prism?

Physics · Geometrical Optics

JEE Main 2025 — 23 January, Evening Shift — Question 50

The refractive index of the material of a glass prism is $\sqrt{3}$ . The angle

of minimum deviation is equal to the angle of the prism. What is the angle of the prism?

\mu =\frac{\operatorname{Sin}\left( \frac{A+{{\delta }_{\min }}}{2} \right)}{\sin \frac{A}{2}}

Given $\delta_{\text {min }}=\mathrm{A}$

$\sqrt{3}=\frac{\sin A}{\sin \frac{A}{2}}=\frac{2 \sin \frac{A}{2} \cos \frac{A}{2}}{\sin \frac{A}{2}}$

$\cos \frac{A}{2}=\frac{\sqrt{3}}{2}$

$A=60^{\circ}$

Answer key and solution verified before publishing.

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