Physics · Rotational Dynamics

JEE Main 2026 — 2 April, Morning Shift — Question 3

The position of an object having mass 0.1kg0.1\mathrm{kg} as a function of time t is given as r⃗=(10t2i⃗+5t3j⃗)m.\vec{\mathrm{r}} = \left(10\mathrm{t}^{2}\vec{\mathrm{i}} +5\mathrm{t}^{3}\vec{\mathrm{j}}\right)\mathrm{m}. At t=1 s \mathrm{t} = 1\mathrm{~s~} , which of the following statements are correct? A. The linear momentum p⃗=(2i⃗+1.5j⃗)kg⋅m/s.\vec{\mathrm{p}} = \left(2\vec{\mathrm{i}} +1.5\vec{\mathrm{j}}\right)\mathrm{kg}\cdot \mathrm{m} / \mathrm{s}. B. The force acting on the object F⃗=(2i⃗+3j⃗)N.\vec{\mathrm{F}} = \left(2\vec{\mathrm{i}} +3\vec{\mathrm{j}}\right)\mathrm{N}. C. The angular momentum of the object about its origin L⃗=15k⃗Js.\vec{\mathrm{L}} = 15\vec{\mathrm{k}}\mathrm{J}\mathrm{s}. D. The torque acting on the object about its origin r⃗=20k⃗Nm.\vec{\mathrm{r}} = 20\vec{\mathrm{k}}\mathrm{N}\mathrm{m}. Choose the correct answer from the option given below.

  1. Option A:

    A, B and C only

  2. Option B:

    B, C and D only

  3. Option C:

    A, C and D only

  4. Option D:

    A, B and D only

    Correct

Answer: D

Step-by-step solution

Given r⃗=10t2i⃗+5t3j⃗⇒r⃗t=1=10i⃗+5j⃗\vec{\mathrm{r}} = 10\mathrm{t}^{2}\vec{\mathrm{i}} +5\mathrm{t}^{3}\vec{\mathrm{j}}\Rightarrow \vec{\mathrm{r}}_{\mathrm{t} = 1} = 10\vec{\mathrm{i}} +5\vec{\mathrm{j}} ... L⃗=r⃗×P⃗=5k⃗\vec{\mathrm{L}} = \vec{\mathrm{r}}\times \vec{\mathrm{P}} = 5\vec{\mathrm{k}}

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Physics
Chapter
Rotational Dynamics
Topic
Angular Momentum and its Conservation
The position of an object having mass 0.1 kg as a function of time t… | JEE Main 2026 PYQ with Solution · DhiX AI