Physics · Units, Dimensions & Error Analysis

JEE Main 2026 — 6 April, Evening Shift — Question 1

The percentage error in the calculated volume of a sphere, if there is $2\%$ error in its diameter measurement, is

Answer: C

Volume $V = \frac{4}{3}\pi R^3$ , diameter $d=2R$ , so $\frac{\Delta V}{V} = 3\frac{\Delta R}{R} = 3\frac{\Delta d}{d} = 3\times 2\% = 6\%$ .

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