Chemistry · Solutions and Colligative Properties

JEE Main 2025 — 7 April, Morning Shift — Question 18

The percentage dissociation of a salt (MX3)\left(\mathrm{MX}_{3}\right) solution at given temperature (van't Hoff factor i=2i=2 ) is _____\_\_\_\_\_ % (Nearest integer)

Answer: 33

Numerical answer — enter this value.

Step-by-step solution

MX3→M3++3X−\text{MX}_3 \rightarrow \text{M}^{3+} + 3\text{X}^- Initial:100Change:−α+α+3αEquilibrium:1−αα3α\begin{array}{lccc} \text{Initial:} & 1 & 0 & 0 \\ \text{Change:} & - \alpha & + \alpha & + 3\alpha \\ \text{Equilibrium:} & 1 - \alpha & \alpha & 3\alpha \end{array} 1+3α=21 + 3\alpha = 2 α=33.33%\alpha = 33.33\%

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Chemistry
Chapter
Solutions and Colligative Properties
Topic
Abnormal Colligative Properties - van't Hoff Factor
The percentage dissociation of a salt ( MX 3 ) solution at given… | JEE Main 2025 PYQ with Solution · DhiX AI