The number of paramagnetic complex among [ FeF 6 6 ] 3- , [ Fe ( CN ) 6 ] 3- , [ Mn ( CN ) 6 ] 3- , [ Co ( C 2 O 4 ) 3 ] 3- , [ MnCl 6 ] 3- and [ CoF 6 ] 3- , which involved d 2 s p 3 hybridization is \ \ \ \ \

Chemistry · Coordination Compounds

JEE Main 2025 — 7 April, Morning Shift — Question 17

The number of paramagnetic complex among $\left[\mathrm{FeF} 6_{6}\right]^{3-},\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-},\left[\mathrm{Mn}(\mathrm{CN})_{6}\right]^{3-},$

$\left[\mathrm{Co}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-}$ , $\left[\mathrm{MnCl}_{6}\right]^{3-}$ and $\left[\mathrm{CoF}_{6}\right]^{3-}$ , which involved $d^{2} s p^{3}$ hybridization is $\_\_\_\_\_$

Answer: 2

Numerical answer — enter this value.

Step-by-step solution

$\left[\mathrm{FeF}_{6}\right]^{3-}$ has $\mathrm{Fe}^{3+}$

\mathrm{n}=5

\mu=\sqrt{35} \text { B.M paramagnetic }

$\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}$ has $\mathrm{SFL}, d^{2} s p^{3} . \mathrm{n}=1$

$\left[\mathrm{Mn}(\mathrm{CN})_{6}\right]^{3-} \mathrm{d}^{4}: \mathrm{t}_{2 \mathrm{~g}}^{4} \mathrm{e}_{\mathrm{g}}^{0}: \mathrm{d}^{2} \mathrm{sp}^{3}$ paramagnetic

$\left[\mathrm{Co}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-}$ has SFL, $d^{2} \mathrm{sp}^{3}$ . diamagnetic

$\left[\mathrm{MnCl}_{6}\right]^{3-}$ has WFL, $s p^{3} d^{2}$ paramagnetic

$\left[\mathrm{CoF}_{6}\right]^{3-}$ has WFL, $s p^{3} d^{2}$ paramagnetic

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 7 April, Morning Shift
Subject: Chemistry
Chapter: Coordination Compounds
Topic: Properties and importance of Coordination Complexes