Chemistry · Redox Reactions

JEE Main 2026 — 23 January, Evening Shift — Question 59

The oxidation state of chromium in the final product formed in the reaction between KI and acidified K2Cr2O7\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} solution is:

  1. Option A:

    +4+4

  2. Option B:

    +3+3

    Correct
  3. Option C:

    +2+2

  4. Option D:

    +6+6

Answer: B

Step-by-step solution

K2Cr2O7+KI→H+I2+Cr3+\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}+\mathrm{KI} \xrightarrow{\mathrm{H}^{+}} \mathrm{I}_{2}+\mathrm{Cr}^{3+}

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Chemistry
Chapter
Redox Reactions
Topic
Types of Redox Reactions & Balancing of Redox Reactions
The oxidation state of chromium in the final product formed in the… | JEE Main 2026 PYQ with Solution · DhiX AI