Chemistry · Coordination Compounds

JEE Main 2025 — 3 April, Morning Shift — Question 15

The number of optical isomers exhibited by the iron complex (A) obtained from the following reaction is _____\_\_\_\_\_ .

FeCl3+KOH+H2C2O4→ A\mathrm{FeCl}_{3}+\mathrm{KOH}+\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4} \rightarrow \mathrm{~A}

Answer: 2

Numerical answer — enter this value.

Step-by-step solution

Complex obtained is [Fe(C2O4)3]3−\left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-}

Total isomers =2( d/l=2(\mathrm{~d} / \mathrm{l} form)

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Chemistry
Chapter
Coordination Compounds
Topic
Isomerism in Coordination Compounds
The number of optical isomers exhibited by the iron complex (A)… | JEE Main 2025 PYQ with Solution · DhiX AI