The molar mass of the water insoluble product formed from the fusion of chromite ore (FeCr 2O 4) with Na 2CO 3 in the presence of O 2 is \ \ \ \ g\,mol -1 .

Chemistry · Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

JEE Main 2025 — 29 January, Morning Shift — Question 19

The molar mass of the water insoluble product formed from the fusion of chromite ore $\mathrm{(FeCr_2O_4)}$ with $\mathrm{Na_2CO_3}$ in the presence of $\mathrm{O_2}$ is $\_\_\_\_\mathrm{g\,mol^{-1}}$ .

Answer: 160

Numerical answer — enter this value.

Step-by-step solution

Fusion of $\mathrm{FeCr_2O_4}$ with $\mathrm{Na_2CO_3}$ in the presence of $\mathrm{O_2}$ gives water soluble $\mathrm{Na_2CrO_4}$ and water insoluble $\mathrm{Fe_2O_3}$ .

$\mathrm{4FeCr_2O_4 + 8Na_2CO_3 + 7O_2 \rightarrow 8Na_2CrO_4 + 2Fe_2O_3 + 8CO_2}$

The water insoluble product is $\mathrm{Fe_2O_3}$ .

Molar mass $= 2 \times 56 + 3 \times 16 = 112 + 48 = 160\,\mathrm{g\,mol^{-1}}$

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Exam: JEE Main 2025
Paper: 29 January, Morning Shift
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry
Topic: Chemical Equations, Stoichiometry and Limiting Reagent

Choose the correct statements. (A) Weight of a substance is the amount of matter present in it (B) Mass is the force exerted by gravity on…

Answer: 160

Step-by-step solution

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