Mathematics · Probability

JEE Main 2026 — 28 January, Morning Shift — Question 14

The mean and variance of 1010 observations are 99 and 34.234.2 , respectively. If 88 of these observations are 2,3,5,10,11,13,15,212,3,5,10,11,13,15,21, then the mean deviation about the median of all the 1010 observations is

  1. Option A:

    5

    Correct
  2. Option B:

    4

  3. Option C:

    6

  4. Option D:

    7

Answer: A

Step-by-step solution

2+3+5+10+11+13+15+21+a+b10=9\frac{2+3+5+10+11+13+15+21+a+b}{10}=9 80+a+b10=9⇒a+b=10\begin{gathered} \frac{80+a+b}{10}=9 \Rightarrow a+b=10 \end{gathered} Σxi210−(Σxi10)2=34.2\frac{\Sigma x_i^2}{10} - \left( \frac{\Sigma x_i}{10} \right)^2 = 34.2

22+32+52+102+112+132+152+212+a2+b210−92=34.2\frac{2^2+3^2+5^2+10^2+11^2+13^2+15^2+21^2+a^2+b^2}{10} - 9^2 = 34.2 1094+a2+b2−810=3421094 + a^2 + b^2 - 810 = 342 a2+b2=58\begin{gathered} a^2 + b^2 = 58 \end{gathered} a=7, b=3a=7,\ b=3 or a=3, b=7a=3,\ b=7

Number: 2, 3, 5, 7, 10, 11, 13, 15, 21 Mean =7+102=8.5=\frac{7+10}{2}=8.5

M.D.=6.5+5.5+5.5+3.5+1.5+1.5+2.5+4.5+6.5+12.510=505=5\mathrm{M.D.} = \frac{6.5+5.5+5.5+3.5+1.5+1.5+2.5+4.5+6.5+12.5}{10} = \frac{50}{5} = 5

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Mathematics
Chapter
Probability
Topic
Mean, variance, expected values of distributions
The mean and variance of 10 observations are 9 and 34.2 … | JEE Main 2026 PYQ with Solution · DhiX AI