Start free

Physics · Units, Dimensions & Error Analysis

JEE Main 2025 — 22 January, Evening Shift — Question 49

The maximum percentage error in the measurment of density of a wire

is[0pt] [Given, mass of wire =(0.60±0.003)g=(0.60 \pm 0.003) \mathrm{g} radius of

wire =(0.50±0.01)cm=(0.50 \pm 0.01) \mathrm{cm} length of wire

(10.00±0.05)cm(10.00 \pm 0.05) \mathrm{cm} ]

  1. Option A:

    4

  2. Option B:

    5

    Correct
  3. Option C:

    8

  4. Option D:

    7

Answer: B

Step-by-step solution

Conceptual

Answer key and solution verified before publishing.

Practise Units, Dimensions & Error Analysis

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free
Exam
JEE Main 2025
Paper
22 January, Evening Shift
Subject
Physics
Chapter
Units, Dimensions & Error Analysis
Topic
Significant Figures and Error Analysis

More Units, Dimensions & Error Analysis questions from this paper

The maximum percentage error in the measurment of density of a wire… | JEE Main 2025 PYQ with Solution · DhiX AI