Physics · Nuclear Physics

JEE Main 2024 — 31 January, Shift 2 — Question 43

The mass number of nucleus having radius equal to half of the radius of nucleus with mass number 192 is:

Option A:
24
Correct
Option B:
32
Option C:
40
Option D:
20

Answer: A

Step-by-step solution

$R_{1}=\frac{R_{2}}{2}$ $\mathrm{R}_{0}\left(\mathrm{~A}_{1}\right)^{1 / 3}=\frac{\mathrm{R}_{0}}{2}\left(\mathrm{~A}_{2}\right)^{1 / 3}$ $\mathrm{A}_{1}=\frac{1}{8} \mathrm{~A}_{2}$ $\mathrm{A}_{1}=\frac{192}{8}=24$

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Exam: JEE Main 2024
Paper: 31 January, Shift 2
Subject: Physics
Chapter: Nuclear Physics
Topic: Introduction to Nucleus and its constituents

A nucleus has mass number A 1 and volume V 1 . Another nucleus has mass number A 2 and volume V 2 . If relation between mass number is A…

Answer: A

Step-by-step solution

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