Physics · Vectors and Scalars

JEE Main 2024 — 31 January, Shift 2 — Question 42

If two vectors $\vec{A}$ and $\vec{B}$ having equal magnitude R are inclined at an angle $\theta$ , then

Option A:
$|\overrightarrow{\mathrm{A}}-\overrightarrow{\mathrm{B}}|=\sqrt{2} \mathrm{R} \sin \left(\frac{\theta}{2}\right)$
Option B:
$|\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}|=2 R \sin \left(\frac{\theta}{2}\right)$
Option C:
$|\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}|=2 R \cos \left(\frac{\theta}{2}\right)$
Correct
Option D:
$|\overrightarrow{\mathrm{A}}-\overrightarrow{\mathrm{B}}|=2 R \cos \left(\frac{\theta}{2}\right)$

Answer: C

With rise in temperature, the Young's modulus of elasticity

Answer key and solution verified before publishing.

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