The magnetic flux φ (in weber) linked with a closed circuit of resistance 8 Ω varies with time (in seconds) as φ=5 t 2 -36 t +1 . The induced current in the circuit at t=2 s is \ \ \ \ \ \ \ A.

Physics · Electromagnetic Induction

JEE Main 2024 — 31 January, Shift 2 — Question 50

The magnetic flux $\phi$ (in weber) linked with a closed circuit of resistance $8 \Omega$ varies with time (in seconds) as $\phi=5 \mathrm{t}^{2}-36 \mathrm{t}+1$ . The induced current in the circuit at $t=2 \mathrm{~s}$ is $\_\_\_\_\_\_\_$ A.

Answer: 2

Numerical answer — enter this value.

Step-by-step solution

$\varepsilon=-\left(\frac{\mathrm{d} \phi}{\mathrm{dt}}\right)=10 \mathrm{t}-36$

at $\mathrm{t}=2, \varepsilon=16 \mathrm{~V}$

$\mathrm{i}=\frac{\varepsilon}{\mathrm{R}}=\frac{16}{8}=2 \mathrm{~A}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 31 January, Shift 2
Subject: Physics
Chapter: Electromagnetic Induction
Topic: Magnetic Flux, Faraday's Law and Lenz's Law