The increase in the pressure required to decrease the volume ( Δ V ) of water is 6.3times10 7 N/m 2 . The percentage decrease in the volume is (Bulk modulus of water = 2.1times10 9 N/m 2 )

Physics · Mechanical Properties of Matter

JEE Main 2026 — 4 April, Morning Shift — Question 2

The increase in the pressure required to decrease the volume ( $\Delta V$ ) of water is $6.3\times10^{7}\mathrm{N/m}^2$ . The percentage decrease in the volume is (Bulk modulus of water = $2.1\times10^{9}\mathrm{N/m}^2$ )

Option A:
$2\%$
Option B:
$3\%$
Correct
Option C:
$6\%$
Option D:
$4\%$

Answer: B

Step-by-step solution

$\beta = -\Delta P/(\Delta V/V)$ ⇒ $\Delta V/V = -\Delta P/\beta = -6.3e7/2.1e9 = -0.03$ ⇒ 3% decrease

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Exam: JEE Main 2026
Paper: 4 April, Morning Shift
Subject: Physics
Chapter: Mechanical Properties of Matter
Topic: Stress,Strain and Modulus of Elasticity

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Answer: B

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