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Physics · Units, Dimensions & Error Analysis

JEE Main 2026 — 4 April, Morning Shift — Question 1

In a screw gauge when the circular scale is given five complete rotations it moves linearly by 2.5mm2.5\mathrm{mm}. If the circular scale has 100 divisions, the least count of screw gauge is mm.

  1. Option A:

    1×10−21\times10^{-2}

  2. Option B:

    1×10−31\times10^{-3}

  3. Option C:

    5×10−55\times10^{-5}

  4. Option D:

    5×10−35\times10^{-3}

    Correct

Answer: D

Step-by-step solution

Pitch = 2.5/5 = 0.5 mm LC = pitch/100 = 0.5/100 = 0.005 mm = 5×10⁻³ mm

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
4 April, Morning Shift
Subject
Physics
Chapter
Units, Dimensions & Error Analysis
Topic
Vernier Calipers and Screw Gauge
In a screw gauge when the circular scale is given five complete… | JEE Main 2026 PYQ with Solution · DhiX AI