Mathematics · Statistics

JEE Main 2024 — 9 April, Shift 1 — Question 16

The frequency distribution of the age of students in a class of 40 students is given below.

Age151617181920
No. of Students58512xy

If the mean deviation about the median is 1.25 , then 4x+5y4 x+5 y is equal to :

  1. Option A:

    43

  2. Option B:

    44

    Correct
  3. Option C:

    47

  4. Option D:

    46

Answer: B

Step-by-step solution

x+y=10......(1)median=18=MM.D=∑f1∣x1−M∣∑f1x+y=10......(1)\\median=18=M \\M.D=\frac{{\displaystyle\sum_{}}f_1\left|x_1-M\right|}{\sum_{}f_1}

1.25=36+x+2y40x+2y=14..............(2)by(1)  &(2)1.25=\frac{36+x+2y}{40}\\x+2y=14..............(2)\\by(1)\;\&(2)

x=6,y=4⇒4x+5y=24+20=44x=6,y=4\\\Rightarrow4x+5y=24+20=44\\\\\\

Age(xi)\left(x_i\right)\\\\\\\\F∥xi−M∥\left\|x_i-M\right\|\\\\\\\\Fi∥xi−M∥F_i\left\|x_i-M\right\|\\\\\\\\
155315
168216
17515
181200
19X1X
20Y22y

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Mathematics
Chapter
Statistics
Topic
Measures of Dispersion
The frequency distribution of the age of students in a class of 40… | JEE Main 2024 PYQ with Solution · DhiX AI