The fractional compression (Δ V/V ) of water at the depth of 2.5 km below the sea level is \ \ \ \ \ \ \% . Given, the Bulk modulus of water =2 × 10 9 Nm -2 , density of water =10 3 kg m -3 , acceleration due to gravity = g =10 ms -2 .

Physics · Fluid Mechanics

JEE Main 2025 — 29 January, Morning Shift — Question 34

The fractional compression $\left(\frac{\Delta V}{V}\right)$ of water at the depth of 2.5 km below the sea level is $\_\_\_\_\_\_$ $\%$ . Given, the Bulk modulus of water $=2 \times 10^{9} \mathrm{Nm}^{-2}$ , density of water $=10^{3} \mathrm{~kg} \mathrm{~m}^{-3}$ , acceleration due to gravity $=\mathrm{g}=10 \mathrm{~ms}^{-2}$ .

Option A:
1.75
Option B:
1
Option C:
1.5
Option D:
1.25
Correct

Answer: D

Step-by-step solution

$B=\frac{\rho g h}{\left(\frac{\Delta v}{v}\right)}$

$\frac{\Delta \mathrm{v}}{\mathrm{v}} \times 100=\frac{\rho \mathrm{gh}}{\mathrm{B}} \times 100$

$\frac{1000 \times 10 \times 2.5 \times 10^{3}}{2 \times 10^{9}} \times 100 \%$ $=1.25 \%$

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Exam: JEE Main 2025
Paper: 29 January, Morning Shift
Subject: Physics
Chapter: Fluid Mechanics
Topic: Properties of Fluids & Hydrostatic Pressure

In a hydraulic lift, the surface area of the input piston is 6 cm^2 and that of the output piston is 1500 cm^2 . If 100 N force is applied…

Answer: D

Step-by-step solution

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