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Chemistry · d and f Block Elements

JEE Main 2024 — 9 April, Shift 2 — Question 72

The electronic configuration of Einsteinium is : (( Given atomic number of Einsteinium =99)=99)

  1. Option A:

    [Rn]5f126 d07 s2[\mathrm{Rn}] 5 \mathrm{f}^{12} 6 \mathrm{~d}^{0} 7 \mathrm{~s}^{2}

  2. Option B:

    [Rn]5f116 d07 s2[\mathrm{Rn}] 5 \mathrm{f}^{11} 6 \mathrm{~d}^{0} 7 \mathrm{~s}^{2}

    Correct
  3. Option C:

    [Rn]5f136 d07 s2[\mathrm{Rn}] 5 \mathrm{f}^{13} 6 \mathrm{~d}^{0} 7 \mathrm{~s}^{2}

  4. Option D:

    [Rn]5f106 d07 s2[\mathrm{Rn}] 5 \mathrm{f}^{10} 6 \mathrm{~d}^{0} 7 \mathrm{~s}^{2}

Answer: B

Step-by-step solution

Einsteinium (atomic No=99)\mathrm{No}=99) : [Rn]5f116 d07 s2[\mathrm{Rn}] 5 \mathrm{f}^{11} 6 \mathrm{~d}^{0} 7 \mathrm{~s}^{2}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
9 April, Shift 2
Subject
Chemistry
Chapter
d and f Block Elements
Topic
Inner transition elements (f-Block elements)

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