Physics · Electrostatics

JEE Main 2024 — 5 April, Shift 2 — Question 56

The electric field at point p due to an electric dipole is $E$ . The electric field at point $R$ on equitorial line will be $\frac{E}{x}$ . The value of $x$ :

Answer: 16

Numerical answer — enter this value.

Step-by-step solution

$\mathrm{E}_{\mathrm{P}}=\frac{2 \mathrm{KP}}{\mathrm{r}^{3}}=\mathrm{E}$

$E_{R}=\frac{K P}{(2 r)^{3}}=\frac{E}{16}$ $\mathrm{x}=16$

Answer key and solution verified before publishing.

Practise Electrostatics

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free

Exam: JEE Main 2024
Paper: 5 April, Shift 2
Subject: Physics
Chapter: Electrostatics
Topic: Electric Dipole

The vehicles carrying inflammable fluids usually have metallic chains touching the ground :

Answer: 16

Step-by-step solution

Practise Electrostatics

More Electrostatics questions from this paper