Physics · Fluid Mechanics

JEE Main 2024 — 5 April, Shift 2 — Question 55

A hydraulic press containing water has two arms with diameters as mentioned in the figure. A force of 10 N is applied on the surface of water in the thinner arm. The force required to be applied on the surface of water in the thicker arm to maintain equilibrium of water is $\qquad$ N . $\frac{\mathrm{F}_{1}}{\pi(7)^{2}}=\frac{10}{\pi \times(0.7)^{2}}$ $\mathrm{F}_{1}=1000 \mathrm{~N}$ 57. The electric field at point p due to an electric dipole is $E$ . The electric field at point $R$ on equitorial line will be $\frac{E}{x}$ . The value of $x$ :

Answer: 1000

Numerical answer — enter this value.

Step-by-step solution

$\frac{F_1}{A_1}=\frac{F_2}{A_2}$

$\frac{{{\text{F}}_{1}}}{\pi {{(7)}^{2}}}=\frac{10}{\pi \times {{(0.7)}^{2}}}$ ${{\text{F}}_{1}}=1000\text{ }\!\!~\!\!\text{ N}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 5 April, Shift 2
Subject: Physics
Chapter: Fluid Mechanics
Topic: Variation of Static Pressure Inside a Liquid