Physics · Motion in one Dimension

JEE Main 2025 — 4 April, Evening Shift — Question 47

The displacement xx versus time graph is shown below.

(A) The average velocity during 0 to 3 s is 10 m/s10 \mathrm{~m} / \mathrm{s}

(B) The average velocity during 3 to 5 s is 0 m/s0 \mathrm{~m} / \mathrm{s}

(C) The instantaneous velocity at t=2 st=2 \mathrm{~s} is 5 m/s5 \mathrm{~m} / \mathrm{s}

(D) The average velocity during 5 to 7 s and instantaneous velocity at t=6.5 st=6.5 \mathrm{~s} are equal

(E) The average velocity from t=0t=0 to t=9 st=9 \mathrm{~s} is zero

Choose the correct answer from the options given below

Question figure
  1. Option A:

    (B), (D), (E) only

  2. Option B:

    (B), (C), (D) only

  3. Option C:

    (A), (D), (E) only

  4. Option D:

    (B), (C), (E) only

    Correct

Answer: D

Step-by-step solution

Vavg t=0V_{\text {avg }} t=0 to t=3⇒53t=3 \Rightarrow \frac{5}{3} Vavg t=3V_{\text {avg }} t=3 to

t=5⇒02=0\mathrm{t}=5 \Rightarrow \frac{0}{2}=0 VV at t=2t=2 is equal to slope =5=5 From t=5t=5 to

t=7t=7 sec slope is not constant so avg velocity is not equal to instantaneous velocity.

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Physics
Chapter
Motion in one Dimension
Topic
Graphical Interpretation of 1-D motion
The displacement x versus time graph is shown below. (A) The average… | JEE Main 2025 PYQ with Solution · DhiX AI