Physics · Semiconductor and Electronic Devices

JEE Main 2025 — 4 April, Evening Shift — Question 46

Consider a $n$ -type semiconductor in which $n_{e}$ and $n_{h}$ are number of electrons and holes, respectively.

(A) Holes are minority carriers

(B) The dopant is a pentavalent atom

(C) $n_{e} n_{h} \neq n_{i}^{2}$ (where $n_{i}$ is number of electrons or holes in semiconductor when it is intrinsic form) (D) $n_{e} n_{h} \geq n_{i}^{2}$

(E) The holes are not generated due to the donors Choose the correct answer from the options given below:

Option A:
(A), (B), (C) only
Option B:
(A), (B), (E) only
Correct
Option C:
(A), (C), (E) only
Option D:
(A), (C), (D) only

Answer: B

Step-by-step solution

$n_{e} n_{h}=n_{i}^{2}$ always holds true so option $\mathrm{C}, \mathrm{D}$ are incorrect.

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 4 April, Evening Shift
Subject: Physics
Chapter: Semiconductor and Electronic Devices
Topic: Intrinsic and Extrinsic Semiconductors