Physics · Units, Dimensions & Error Analysis

JEE Main 2024 — 1 February, Shift 1 — Question 42

The dimensional formula of angular impulse is :

Option A:
$\left[\mathrm{M} \mathrm{L}^{-2} \mathrm{~T}^{-1}\right]$
Option B:
$\left[\mathrm{M} \mathrm{L}^{2} \mathrm{~T}^{-2}\right]$
Option C:
$\left[\mathrm{M} \mathrm{L} \mathrm{T}^{-1}\right]$
Option D:
) $\left[\mathrm{M} \mathrm{L}^{2} \mathrm{~T}^{-1}\right]$
Correct

Answer: D

Step-by-step solution

Angular impulse = change in angular momentum. [Angular impulse $]=[$ Angular momentum $]=[\mathrm{mvr}]$ $=\left[\mathrm{M} \mathrm{L}^{2} \mathrm{~T}^{-1}\right]$

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Exam: JEE Main 2024
Paper: 1 February, Shift 1
Subject: Physics
Chapter: Units, Dimensions & Error Analysis
Topic: Units and Dimensions Analysis

Answer: D

Step-by-step solution

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