Physics · Units, Dimensions & Error Analysis
JEE Main 2024 — 1 February, Shift 1 — Question 39
10 divisions on the main scale of a Vernier calliper coincide with 11 divisions on the Vernier scale. If each division on the main scale is of 5 units, the least count of the instrument is :
- Option A:
- Option B:
- Option C:
- Option D:Correct
Answer: D
Step-by-step solution
\begin{array}{*{35}{r}}{} & 1\text{VSD}=\frac{10}{11}\text{MSD} \\{} & \text{LC}=1\text{MSD}-1\text{VSD} \\{} & ~=1\text{MSD}-\frac{10}{11}\text{MSD} \\{} & ~=\frac{1\text{MSD}}{11} \\{} & ~=\frac{5}{11}\text{ }\!\!~\!\!\text{ units }\!\!~\!\!\text{ } \\\end{array}
Answer key and solution verified before publishing.
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- Exam
- JEE Main 2024
- Paper
- 1 February, Shift 1
- Subject
- Physics
- Chapter
- Units, Dimensions & Error Analysis
- Topic
- Vernier Calipers and Screw Gauge