The cycloalkane ( X ) on bromination consumes one mole of bromine per mole of ( X ) and gives the product ( Y ) in which C : Br ratio is 3: 1 . The percentage of bromine in the product ( Y ) is \ \ \ \ \%. (Nearest integer) (Given : Molar mass in g mol -1 H : 1, C : 12 , O : 16, Br : 80 )

Chemistry · Hydrocarbons

JEE Main 2026 — 22 January, Morning Shift — Question 66

The cycloalkane ( X ) on bromination consumes one mole of bromine per mole of ( X ) and gives the product ( Y ) in which $\mathrm{C}: \mathrm{Br}$ ratio is $3: 1$ . The percentage of bromine in the product ( Y ) is $\_\_\_\_$ $\%.$ (Nearest integer) (Given : Molar mass in $\mathrm{g} \mathrm{mol}^{-1} \mathrm{H}: 1, \mathrm{C}: 12$ , $\mathrm{O}: 16, \mathrm{Br}: 80$ )

Answer: 66

Numerical answer — enter this value.

Step-by-step solution

$\mathrm{C}_{6} \mathrm{H}_{10} \xrightarrow{\mathrm{Br}_{2}} \mathrm{C}_{6} \mathrm{H}_{10} \mathrm{Br}_{2}$ Molecular mass of $\mathrm{C}_{6} \mathrm{H}_{10} \mathrm{Br}_{2}$ is : $12 \times 6+10+160$ $72+10+160=242$ % of $\mathrm{Br}=\frac{160}{242} \times 100$ % of $\mathrm{Br}=66.11 \% \approx 66 \%$

Answer key and solution verified before publishing.

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Exam: JEE Main 2026
Paper: 22 January, Morning Shift
Subject: Chemistry
Chapter: Hydrocarbons
Topic: Properties & Uses of Alkenes and Dienes