The current flowing through the 1 Ω resistor is frac n 10 A. The value of n is .

Physics · Current Electricity

JEE Main 2024 — 9 April, Shift 1 — Question 59

The current flowing through the $1 \Omega$ resistor is $\frac{\mathrm{n}}{10}$ A. The value of $n$ is $\qquad$ .

Numerical answer — enter this value.

$\frac{\text{y}-5}{2}+\frac{\text{y}-0}{2}+\frac{\text{y}-\text{x}+10}{1}=0$

$\begin{array}{*{35}{r}}{} & y-5+y+2y-2x+20=0\\\end{array}$

$\frac{x-5}{4}+\frac{x-0}{4}+\frac{x-10-y}{1}=0$

$x-5+x+4x-40-4y=0$$6x-4y-45=0\text{ }\!\!~\!\!\text{ }$ ..(i)

$\frac{-2x+4y+15=0}{4x-30=0}$

$x=\frac{15}{2}\And 4y-15+15=0$$y=0$

$\text{i}=\frac{\text{y}-\text{x}+10}{1}$$\text{i}=\frac{0-7.5+10}{1}$

$\text{i}=2.5\text{ }\!\!~\!\!\text{ A}=\frac{\text{n}}{10}\text{ }\!\!~\!\!\text{ A}$

$\text{n}=25$

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