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Chemistry · Structure of Atom

JEE Main 2024 — 29 January, Shift 1 — Question 63

The correct set of four quantum numbers for the valence electron of rubidium atom (Z=37)(Z=37) is:

  1. Option A:

    5,0,0,+125,0,0,+\frac{1}{2}

    Correct
  2. Option B:

    5,0,1,+125,0,1,+\frac{1}{2}

  3. Option C:

    5,1,0,+125,1,0,+\frac{1}{2}

  4. Option D:

    5,1,1,+125,1,1,+\frac{1}{2}

Answer: A

Step-by-step solution

The configuration of Rubidium is [Kr] 5s1[Kr]\,5s^1

For 5s electron, we have

n=5, ℓ=0n=5,\ \ell=0 mℓ=0, s=+12m_\ell=0,\ s=+\frac{1}{2}

So the correct set is 5,0,0,+125,0,0,+\frac{1}{2}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
29 January, Shift 1
Subject
Chemistry
Chapter
Structure of Atom
Topic
Quantum Numbers and Sommerfeld
The correct set of four quantum numbers for the valence electron of… | JEE Main 2024 PYQ with Solution · DhiX AI