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Chemistry · Aldehydes and Ketones

JEE Main 2024 — 30 January, Shift 1 — Question 74

The compound formed by the reaction of ethanal with semicarbazide contains ____\_\_\_\_ number of nitrogen atoms.

Answer: 3

Numerical answer — enter this value.

Step-by-step solution

Ethanal (CH3CHO) reacts with semicarbazide (NH2NHCONH2) to form a semicarbazone.\text{Ethanal (CH}_3\text{CHO) reacts with semicarbazide (NH}_2\text{NHCONH}_2) \text{ to form a semicarbazone.} The reaction involves the carbonyl group of ethanal reacting with the −NH2 group of semicarbazide.\text{The reaction involves the carbonyl group of ethanal reacting with the } -\text{NH}_2 \text{ group of semicarbazide.} The product formed is CH3CH=N-NHCONH2\text{The product formed is CH}_3\text{CH=N-NHCONH}_2 Counting nitrogen atoms: one from −CH=N-, one from −NH-, and one from −CONH2⇒Total = 3\text{Counting nitrogen atoms: one from } -\text{CH=N-}, \text{ one from } -\text{NH-}, \text{ and one from } -\text{CONH}_2 \Rightarrow \text{Total = 3} 3\boxed{3}

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Exam
JEE Main 2024
Paper
30 January, Shift 1
Subject
Chemistry
Chapter
Aldehydes and Ketones
Topic
Chemical properties of Aldehydes & Ketones

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