Chemistry · Solid State

JEE Main 2024 — 30 January, Shift 1 — Question 73

On a thin layer chromatographic plate, an organic compound moved by 3.5 cm , while the solvent moved by 5 cm . The retardation factor of the organic compound is $\_\_\_\_$ $\times 10^{-1}$

Answer: 7

Numerical answer — enter this value.

Step-by-step solution

\text{Given:} \quad \text{Distance moved by compound} = 3.5\ \text{cm}, \quad \text{Distance moved by solvent} = 5\ \text{cm}

\text{Rf} = \frac{\text{Distance moved by compound}}{\text{Distance moved by solvent}} = \frac{3.5}{5} = 0.7

\text{Rf} = 7 \times 10^{-1}

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 30 January, Shift 1
Subject: Chemistry
Chapter: Solid State
Topic: Distillation and chromatography