Mathematics · Statistics

JEE Main 2026 — 4 April, Morning Shift — Question 33

Suppose that the mean and median of the non-negative numbers $21, 8, 17, a, 51, 103, b, 13, 67, (a > b),$ are $40$ and $21,$ respectively. If the mean deviation about the median is $26$ , then $2a$ is equal to:

Option A:
109
Option B:
117
Option C:
161
Option D:
131
Correct

Answer: D

Step-by-step solution

8, 13, b, 17, 21, 51, a, 67, 103

\begin{array}{r} \operatorname{mean}=40=\frac{280+a+b}{9} a+b=80 \end{array}

mean deviation about median $=\frac{13+8+4+30+46+82+(\mathrm{a}-21)+(21-\mathrm{b})}{9}=26$

a-b=51

$\Rightarrow 2 \mathrm{a}=131$

Answer key and solution verified before publishing.

Practise Statistics

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free

Exam: JEE Main 2026
Paper: 4 April, Morning Shift
Subject: Mathematics
Chapter: Statistics
Topic: Measures of Central Tendency